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Answered by **Guest**

T1 - the time the trains are moving to each other.

For time t1, first train will go the distance 70*t.

The second train, for time t will go the distance 60*t.

Both for time t1 - 70t+60(t1)=(70+60)*(t1).

45 - (70+60)*t is the distance between trains that left after t hours.

For the first time they will be 10 miles apart when they are moving to each other

45 - (70+60)*t = 10

45-10=(70+60)*t

35=130*t

t=**35/130 h =7/26 h**≈ 0.27 h

The train meet when distance=0

45 - (70+60)*t=0

45=130t

t=**45/130 h = 9/26 h **≈0.35 h **when trains met.**Trains began to move apart from each other after 9/26 h moving,

After t2 time trains will be (70+60)*(t2)=130*(t2) mi apart from each other.

130*(t2)=10

t2=

so after beginning of the movement it will be

time when they met + time when they are moved 10 mi apart from each other

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